the numearater of a fraction is 3 more than the denominator . if the numearater and denominator are increased by 5 fraction becomes 10 by 7 .find the fraction
Answers
Answer:
5/2
Step-by-step explanation:
Let the denominator be 'a'. Then the numerator should be 3 more than 'a'. Orig. denominator = a
Orig. numerator = a + 3
Fraction is (a + 3)/a.
In question, if both are increased by 5, fraction becomes 10/7:
→ (orig. num. + 5)/(orig. deno. + 5)=10/7
→ (a + 3 + 5)/(a + 5) = 10/7
→ 7(a + 8) = 10(a + 5)
→ 7a + 56 = 10a + 50
→ 56 - 50 = 10a - 7a
→ 6 = 3a
→ 2 = a
Therefore, fraction is:
→ (2 + 3)/2
→ 5/2
Answer:
5/2
Step-by-step explanation:
Assume that the numerator is x and denominator is y.
The numearater of a fraction is 3 more than the denominator.
→ x = y + 3 .............(1)
If the numearater and denominator are increased by 5 fraction becomes 10 by 7.
As per given condition,
→ (x + 5)/(y + 5) = 10/7
→ 7x + 35 = 10y + 50
→ 7(y + 3) + 35 = 10y + 50
→ 7y + 56 = 10y + 50
→ 3y = 6
→ y = 2
Substitute value of y in (1)
→ x = 2 + 3
→ x = 5
Hence, the fraction is x/y = 5/2.