Question

The numerator and the denominator of a fraction are in the ratio 3:2. I 3 is added to the numerator
and 2 is subtracted from the denominator, a new fraction is formed whose value is Find the original
fraction​

Answer 1

$\huge{\underline{\mathtt{\red{❥A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$

The numerator and the denominator of a fraction are in the ratio 3:2.

Assume that the number is 3x and denominator be 2x.

Also said that, if 3 is added to the numerator and 2 is subtracted from the denominator, a new fraction is formed.

As per given condition,

→ (3x + 3)/(2x - 2) = 9/4

→ 4(3x + 3) = 9(2x - 2)

→ 12x + 12 = 18x - 18

→ 6x = 30

→ x = 5

Therefore,

Numerator = 3x = 3(5) = 15

Denominator = 2x = 2(5) = 10

Hence, the fraction is 15/10.

Answer 2

Answer:

The numerator and the denominator of a fraction are in the ratio 3:2.

Assume that the number is 3x and denominator be 2x.

Also said that, if 3 is added to the numerator and 2 is subtracted from the denominator, a new fraction is formed.

As per given condition,

→ (3x + 3)/(2x - 2) = 9/4

→ 4(3x + 3) = 9(2x - 2)

→ 12x + 12 = 18x - 18

→ 6x = 30

→ x = 5

Therefore,

Numerator = 3x = 3(5) = 15

Denominator = 2x = 2(5) = 10

Hence, the fraction is 15/10.