The numerator of a fraction is 1 less than the denominator. If 3 is added to each of the numerator and denominator, the fraction is increased by 3/28. Find the fraction.
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Answered by
5
Let the numerator be x
and denominator be y
Therefore the fraction is x/y
A.T.Q.---
x+1=y. ……(i)
x+3/y+3=x/y+3/28. ……(ii)
On solving equations (i) and (ii)
x/y=-17/18
and denominator be y
Therefore the fraction is x/y
A.T.Q.---
x+1=y. ……(i)
x+3/y+3=x/y+3/28. ……(ii)
On solving equations (i) and (ii)
x/y=-17/18
Answered by
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Let the Denominator = x
numerator = (x-1)
fraction = numerator/denominator
Fraction = x-1/x
A.T.Q
x-1+3/x+3 = x-1/x + 3/28
x+2/x+3 = 28x - 28 + 3x/ 28x
28x(x+2) = (31x - 28)(x+3)
28x² + 56x = 31x² - 28x + 93x - 84
31x² - 28x² + 93x - 28x - 56x - 84
3x² + 9x - 84
[ Divide by 3]
x²+ 3x - 28
x²+ 7x - 4x - 28
x(x+7) -4(x+7)
(x-4) (x+7)
x = 4 or -7 [x is a natural number, x>0]
Hence , x= 4
Fraction = x-1/ x = 4-1 /4 = ¾
Hence, the fraction is 3/4
_________________________
thanks...
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⤵️⤵️⤵️⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Let the Denominator = x
numerator = (x-1)
fraction = numerator/denominator
Fraction = x-1/x
A.T.Q
x-1+3/x+3 = x-1/x + 3/28
x+2/x+3 = 28x - 28 + 3x/ 28x
28x(x+2) = (31x - 28)(x+3)
28x² + 56x = 31x² - 28x + 93x - 84
31x² - 28x² + 93x - 28x - 56x - 84
3x² + 9x - 84
[ Divide by 3]
x²+ 3x - 28
x²+ 7x - 4x - 28
x(x+7) -4(x+7)
(x-4) (x+7)
x = 4 or -7 [x is a natural number, x>0]
Hence , x= 4
Fraction = x-1/ x = 4-1 /4 = ¾
Hence, the fraction is 3/4
_________________________
thanks...
nice to help you ✌️✌️
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