Question

the numerator of a fraction is 3 less than its denominator . if 2 is added to both the numerator and the denominator, then the sum of new fraction and the original fraction is 29/20. find the original fraction
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Answer 1

Step-by-step explanation:

Numerator  is x-3

The fraction is (x-3)/x

when 2 is added to numerator and denominator

                              

  we have fraction as (x-1)/(x+2) 

A/Q  (x-3)/x +(x-1)/(x+2)= 29/20

   ⇒    (x-3)((x+2) +x(x-1)=x(x+2)*29/20

   ⇒    (x²-6-x + x²-x)20= 29x²+58x

   ⇒    40x²-120-40x=29x²+58x

   ⇒    11x²-98x- 120=0

   ⇒    11x² - 110x +12x -120=0

   ⇒     (11x+12)(x-10)=0

Canceling the negative fraction value  of x we have x=10

Then the fraction (x-3)/x=7/10

Answer 2

Answer:

Let the denominator be x            Numerator  is x-3The fraction is (x-3)/xwhen 2 is added to numerator and denominator                                  we have fraction as (x-1)/(x+2)  ATQ  (x-3)/x +(x-1)/(x+2)= 29/20   ⇒    (x-3)((x+2) +x(x-1)=x(x+2)*29/20   ⇒    (x²-6-x + x²-x)20= 29x²+58x   ⇒    40x²-120-40x=29x²+58x   ⇒    11x²-98x- 120=0   ⇒    11x² - 110x +12x -120=0   ⇒     (11x+12)(x-10)=0Canceling the negative fraction value  of x we have x=10Then the fraction (x-3)/x=7/10

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