Question

the numerator of a fraction is 3 less than the denominator if both the numerator and the denominator are increased by 2 the new fraction becomes 6/7 find the original fraction​

Answer 1

Answer:

The original fraction is $\frac{16}{19}$.

Step-by-step explanation:

Let the original fraction be $\frac{x}{y}$.

It is provided that:

x = y - 3

And, $\frac{y-3+2}{y+2}=\frac{6}{7}$

Compute the value of y as follows:

$\frac{y-3+2}{y+2}=\frac{6}{7}\\\frac{y-1}{y+2}=\frac{6}{7}\\7y-7=6y+12\\y=19$

Then the value of x is,

x = y - 3

  = 19 - 3

  = 16

Thus, the original fraction is $\frac{16}{19}$.