The numerator of a fraction is 3 less than the denominator.if both the numerator and denominator are increased by 2,the new fraction becomes 6/7.find the original number
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Answered by
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let numerator =x
denominator=y
fraction=x/y
given=deno.minator=7-2=5
numerator=5-3=2
original fraction=2/5
denominator=y
fraction=x/y
given=deno.minator=7-2=5
numerator=5-3=2
original fraction=2/5
Answered by
2
Hey...!!!
Let the denominator be x
So, numerator = x - 3
Therefore,
(X - 3 - 2)/(x - 2) = 6/7
(X - 5)/(x - 2) = 6/7
7(x - 5) = 6( x - 2)
7x - 35 = 6x - 12
7x - 6x = - 12 + 35
X = 23
So, original fraction is (23 - 3)/23
= 20/23
Hope it helps...!!!
Let the denominator be x
So, numerator = x - 3
Therefore,
(X - 3 - 2)/(x - 2) = 6/7
(X - 5)/(x - 2) = 6/7
7(x - 5) = 6( x - 2)
7x - 35 = 6x - 12
7x - 6x = - 12 + 35
X = 23
So, original fraction is (23 - 3)/23
= 20/23
Hope it helps...!!!
Aastha077:
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