The numerator of a fraction is 3 less than the denominator.If both the numerator and denominator are increased by 2.find the original fraction
Answers
Answered by
67
Correct Question :
The numerator of a fraction is 3 less than the denominator.If both the numerator and denominator are increased by 2 , then the fraction obtained is 6/7 .Find the original fraction .
Given :
- Numerator of a fraction is 3 less than the denominator.
- If both the numerator and denominator are increased by 2 , then the fraction obtained is 6/7 .
To Find :
- The original fraction .
Solution :
As Given that Numerator of a fraction is 3 less than the Denominator. So ,
Now ,
- If both the numerator and denominator are increased by 2 , then the fraction obtained is 6/7 .
A.T.Q :
Value of x is 19 ...
Therefore :
So , The Original Fraction is 16/19 ....
Answered by
8
Answer:
★16/19
Correct Question
- The numerator of a fraction is 3 less than the denominator. if both the numerator and denominator are increased by 2,the new fraction becomes 6/7.Find the original fraction?
Solution
★Let the denominator of the fraction be X.
★Then the numerator of the fraction = (X-3)
★Fraction = Numerator/Denominator = X-3/X.
★Numerator and denominator are increased by 2 then the Numerator and denominator becomes (X-3+2) and (X+2).
★Fraction = Numerator/Denominator =(X-3+2)/(X+2).
★According to question,
- (X-3+2)/(X+2) = 6/7
- X-1/X+2 = 6/7
- 7(X-1) = 6(X+2)
- 7X-7 = 6X+12
- 7X-6X= 12+7
- X = 19
★Therefore
- Numerator = (X-3) = (19-3) = 16
- And,
- Denominator =(X) = 19
★Therefore,
- Original Fraction = Numerator/Denominator
- =(X-3)/X
- = 16/19
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