Question

the numerator of a fraction is 4 less than the denominator if the numerator is decreased by 2 and denominator is increased by 1 the denominator is 8 times the numerator find the fraction

Answer 1

numerator-x
denominator-y
x+4=y
x-y=-4....1
$8(x - 2) = y + 1 \\ 8x - 16 = y + 1 \\ 8x - y = 17.....2$
subtracting 1 and 2
$x - y = - 4 \\ - (8x - y) = - 17 \\ - 7x = - 21 \\ x = 3$
put x=3 in 1
$x - y = - 4 \\ 3 - y = - 4 \\ y = 7$
numerator 3 and denominator 7.