the numerator of a fraction is 6 less than the denominator. if 3 is added to the numerator the fraction is equal to2÷3. find the original fraction
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the denominator = x
Numerator = x - 6
Original fraction = ( x - 6 ) / x ---( 1 )
According to the problem given,
( x - 6 + 3 ) / x = 2/3
( x - 3 ) / x = 2 / 3
3( x - 3 ) = 2x
3x - 9 = 2x
3x - 2x = 9
x = 9
Put x = 9 in equation ( 1 ),
Original fraction = ( x - 6 ) / x
= ( 9 - 6 ) / 9
= 3 / 9
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