The numerator of the fraction is 2 less than the denominator if 1 is added to both numerators and denominators the sum of the new one original fraction is 19 by 15 find the original fraction
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Answered by
76
Let numerator be x
Then denominator=x+2(becauuse numerator is 2 less than it)
If 1 is added to both. Then
x+1/x+2+1=19/15
x+1/x+3=19/15
15(x+1)=19(x+3)
15x + 15=19x + 57
15x-19x=57-15. forget it i should have made in copy
Answered by
60
The original fraction is 3/5
let the numerator be x then,
denominator will be x+2.
according to given condition we get
x/x+2 + x+1/x+2+1 = 19/15
solving this we get quadratic equation
11x²-5x-84=0
solving this we have
x=3
original fraction = x / x+2
= 3 / 3+2
= 3/5
Ans: 3/5
let the numerator be x then,
denominator will be x+2.
according to given condition we get
x/x+2 + x+1/x+2+1 = 19/15
solving this we get quadratic equation
11x²-5x-84=0
solving this we have
x=3
original fraction = x / x+2
= 3 / 3+2
= 3/5
Ans: 3/5
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