Question

the object is placed at right angle to the principal axis of concave mirror at the distance of 30cm from the pole the image formed is real and twice the size of the object find another postion of the object so that tge size of the image will be again twice the object​

Answer 1

given,

Focal length= 30cm if u= -x

real = same said = -ve

magnification , m = v/u = v = m X u =

3 X (-x) = - 3x

from mirror formula = 1/f = 1/v +1/ u

we get 1/-30 =1/-3x + 1/ -x = 1+3/ 3x

= 3x / 4 = 3

X= 40 cm

I hope it will help you Ankit ✌️

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Answer 2

Answer:

thoda sahisai type Karo..

kuch smaj nae aya