Question

the object thrown upward reaches the highest point in 5.0s find the velocity with which it was thrown

Answer 1

hello mate here is ur ans

given

final velocity=0
initial velocity ,u
a=g=9.8m/s , but we need to take -g here since object is opposite to gravity
then by Newton's 1st equation , we have
v=u-gt
since v=0.,
therefore 0=v-gt
v=gt
v= 9.8×5
v=49m/s hence this is the ans

##### be brainly

Answer 2

if it reaches highest point(where it comes to rest) in 5 sec
we know acceleration = a = -g
v = 0
u = ?
t = 5 sec
v= u + at
0 = u + (- g )t
u = gt
if g = 9.8 ms-2. ........... if g = 10 ms-2
u = (9.8)5. ................. u = (10)5
u = 49 m/s. ......................... u = 50 m/s