Chemistry, asked by raianjali828, 8 months ago

the observed dipole moment for a molecule AB is 1.45D and bond length is 1.625aungustron calculate the percentage of ionic character in the bond​

Answers

Answered by rashmimarkam90
0

Answer:

Electrophilic addition on a Carbon-Carbon double bond leads to the formation of a more stable Carbocation intermediate. This statement is called:

Zaitsev's rule

Answered by nancychaterjeestar29
0

Answer:

55 %

Explanation:

GIVEN ; a) observed dipole moment = 1.45 D

             b) bond length = 1.625 A°

TO FIND ; the percentage of ionic character in the bond​

FORMULA USED ; a) % ionic character = observed dipole/theoretical dipole ×100

b) dipole movement = q*d

⇒ q  = charge

⇒ d = bond length

putting the value to get theoretical  dipole movement

1.6 ×10^-19 × 1.625 A° -------------------------- EQUATION 1

putting the value in second formula

% ionic character = 1.45/1.6 *10^-19 * 1.625 *10^-10 * 100

⇒ 55 %

#SPJ2

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