Question

the odometer car 2099 km and the trip 2400km and the and of the trip trip took 8 hours took calculate the average of

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Answer 1

Explanation:

It is given that the total distance travelled by the car is 2400 km-2000 km = 400 km, that is, 400000 m and the total time taken =8 hours, that is, 8×60×60=28800seconds..

Average speed in km/hr = total distance/total time = 400/8 = 50 km/hr.

Average speed in m/s = total distance/total time = 400000/28800 = 13.89 m/s.

Answer 2

$\dag \: \underline{\sf AnsWer :}$

• We are given the, distance at the start of the trip as 2099 km and distance at the end of trip as 2400 km and time interval is 8 hours and we are asked to find the average speed of the car. So, first we need to find the total distance travelled by the car in km/hr . So, let's solve :

$\bigstar \: \: \underline{\textbf{Total distance travelled by the car :}}$

$:\implies \sf{Total \: distance \: =distance \: traveled \: at \: the \: end \: of \: the \: trip - distance \: traveled \: at \: the \: start \: of \: the \: trip}$

$:\implies\textsf {Total distance = 2400 - 2099}$

$:\implies \underline{ \boxed{\textsf {Total distance = 301 km}}}$

$\bigstar \: \: \underline{\textbf{Average Speed of the car :}}$

$\dashrightarrow\:\:\sf Average \: Speed = \dfrac{Total \: distance}{Time \: Interval}$

$\dashrightarrow\:\:\sf Average \: Speed = \dfrac{301}{8}$

$\dashrightarrow\:\: \underline{ \boxed{\sf Average \: Speed = 37.625 \:km/hr }}$