Question

The odometer od a car reads 2000 km at the start of the trip & 2400 km at the end of the trip . If the trip took 8h, Calculate the average speed of a car in km h^-1 m s^-1

Answer 1

$\huge\sf \green{\underline{\red{\underline{\blue{\underline{\orange{Question :-}}}}}}}$

The odometer of a car reads 2000 km at the start of the trip & 2400 km at the end of the trip . If the trip took 8h, Calculate the average speed of a car in km ${h}^{-1} {m s}^{-1}.$

$\huge\sf \green{\underline{\red{\underline{\blue{\underline{\orange{Solution :-}}}}}}}$

$\huge\tt \underline\red{Given :-}$

1. Initial = 2,000 km
2. Final = 2,400 km
3. Time = 8 hrs

$\huge\tt \underline\red{To \: Find :-}$

• The average speed of a car in km ${h}^{-1} {m s}^{-1}$

$\huge\tt \underline\red{Formula \: Used :-}$

1. Distance = Final (F) - Initial (I)
2. Average speed = $\frac{Total \: Distance}{Time \: Taken}$

$\huge\tt \underline\red{Solution :-}$

★ First we will use 1st Formula ★

Distance = Final - Initial

→ 2,400 - 2,000

→ 400 km

★ Now, we will use 2nd Formula ★

Average speed = $\frac{Total \: Distance}{Time \: Taken}$

→ $\frac{\cancel{400} \: km}{\cancel{8} \: hrs}$

→ ${50 km \: hr}^{-1}$

In meter per second

→ $\cancel{50} \times \frac{5}{\cancel{18}}$

→ $\frac{125}{9}$

→ ${13.9 m/s}^{-1}$

Answer 2

Answer:

Initial = 2,000 km

Final = 2,400 km

Time = 8 hrs

\huge\tt \underline\red{To \: Find :-}

ToFind:−

The average speed of a car in km {h}^{-1} {m s}^{-1}h

−1

ms

−1

\huge\tt \underline\red{Formula \: Used :-}

FormulaUsed:−

Distance = Final (F) - Initial (I)

Average speed = \frac{Total \: Distance}{Time \: Taken}

TimeTaken

TotalDistance

\huge\tt \underline\red{Solution :-}

Solution:−

★ First we will use 1st Formula ★

Distance = Final - Initial

→ 2,400 - 2,000

→ 400 km

★ Now, we will use 2nd Formula ★

Average speed = \frac{Total \: Distance}{Time \: Taken}

TimeTaken

TotalDistance

→ \frac{\cancel{400} \: km}{\cancel{8} \: hrs}

8

hrs

400

km

→ {50 km \: hr}^{-1}50kmhr

−1

In meter per second

→ \cancel{50} \times \frac{5}{\cancel{18}}

50

×

18

5

→ \frac{125}{9}

9

125

→ {13.9 m/s}^{-1}13.9m/s

−1