Question

.The odometer of a car reads 2000 km at the start of a trip and 2400 km at the end of the trip. If the trip took 8 h,

calculate the average speed of the car in km h–1 and m s–1​

Answer 1

Final Answer:

Average speed of car (km/h) = 50 km/hr

Average speed of car (m/s) = 13.88 m/s

Explanation:

Distance measured by odometer at start = 2000 km

Distance measured by odometer at end = 2400 km

∴ Total Distance travelled = 2400-2000 = 400 km

Time taken = 8 hours

Now,

Average Speed = $\frac{Total Distance}{Time }$

⇒ Average speed of car (km/h) = $\frac{400}{8}$ = 50 km/hr

⇒ Average speed of car (m/s) = $50$ × $\frac{5}{18}$ = 13.88 m/s [Remember, we multiply km/h with 5/18 to convert it to m/s]

PS : try writing out the given values in the question at start to make your work easier.

Hope it helps :)

(If you find any mistakes, which I am sure there aren't any, then please contact me within 10 minutes of writing this answer, if not possible, please forgive me)

If you have any other queries, feel free to disturb me again.

Answer 2

❄️ Solution :

Distance covered by the car,

s = 2400 km – 200 km = 400 km

Time elapsed, t = 8 h

Average speed of the car is,

$v_{aw} = \sf \dfrac{s}{t} = \dfrac{400 \: km}{8 \: h} \\ \\ \sf = 50 \: km \: h {}^{ - 1} \\ \\ \sf= 50 \: \frac{km}{h} \times \frac{1000 \: m}{1 \: km} \times \frac{1 \: h}{3600s} \\ \\ \sf \: = \pink{13.9 \: m \: s {}^{ - 1} }$

The average speed of the car is 50 km $\sf h^{-1}$ or 13.9 m $\sf s^{-1}$.