Chemistry, asked by cherukuanudeep, 8 months ago

The of a salt, having the general formula MX2, in water is . The concentration of M2+ ions in the aqueous solution of the salt is

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Answered by Anonymous
0

Answer:

ᴛʜᴇ sᴏʟᴜʙɪʟɪᴛʏ ᴘʀᴏᴅᴜᴄᴛ ᴏғ ᴀ sᴀʟᴛ ʜᴀᴠɪɴɢ ɢᴇɴᴇʀᴀʟ ғᴏʀᴍᴜʟᴀ ᴍx2,

ɪɴ ᴡᴀᴛᴇʀ ɪs 4 × 10^–12.

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Answered by ʙʀᴀɪɴʟʏᴡɪᴛᴄh
4

The solubility product of a salt having general formula MX2, in water is 4 × 10^-¹².

Solubility product= 4×10−¹²

MX²⇌M²++2X−

                (s)         (2s)²

                (s)          4s²

(s)(4s²)= Solubility product

4s³=4×10−¹²

⇒s³=10−¹²

⇒s=10−⁴M

Concentration of M2+ ions = s=1×10−⁴M

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