Question

the oH of 0.005 M H2SO4 is​

Answer 1

Explanation:

The pOH of a base is defined as the negative logarithm of hydroxide ion concentration. The product of hydrogen ion and hydroxide ion is equal to 1.0×10−14. ⇒[OH−]=10−2M. Thus, the concentration of [OH]− of 0.005 M H2SO4 is 10−2M.

Answer 2

Explanation:

Molarity is no of moles of solute/volume of aol in litres

So no of moles of solute is 0.005*0.3=0.0015

As in the solute we have 2OH we hav to multiply 2 with 0.0015 and that gives 0.0030l