Question

The oil is heated to 70oC. It cools to 50oC after 6 minutes. Calculate the time taken by the oil to cool from 50oC to 40oC given the surrounding temperature Ts = 25oC.​

Answer 1

Step-by-step explanation:

Newton's cooling law  dtdθ=−k(θ−θ0)

putting the given values of the situation in the formula we get:-

5(70−50)=−k(70−20)

=>520=−k(50)

=>−k=252

now, oil heated at 500C for 10 min

let temperature after 10 min be T 

10(50−T)=252(50−20)

10(50−T)=512

50−T=24

T=50−24

T=260C