The one’s digit in a two-digit number is three less than the ten’s digit. If we interchange the digits in the number and add this new number to the original number, the sum is 77. Find this number.
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Answered by
3
Answer:
52
Step-by-step explanation:
Let ten's digit be 'x'
then one's digit 'y'.y=x-3...... (i)
Original number = 10x+y
Reversed number = 10y+x
sum = 77
(10x+y)+(10y+x)= 77
10x+y+10y+x=77
11x+11y=77
x+y=7
from (i)
x+x-3=7
2x-3=7
2x=10
so,x=5
y=5-3
y=2
ten's digit= 5
one's digit= 2
Original number = 10x+y
= 50+2
=52
ANSWER = 52
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