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Answer:
35° , 75°
Step-by-step explanation:
given...
in ∆ABC...<A is bisected hence....
<BAD = <DAC = x (say)
now...in ∆ ADC.....AD = DC hence..
<DAC = <C = x ( angles opp to eql sides)
therefore...
x + x = <ADC ( extr angl property)
2x = 70° (given)
x = 35°
hence...
A= x + x = 35°+35° = 70°
<ACD = x = 35°
<ABD = ( 180°-A-C ) = 75°
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