Question

The one who will solve this problem he will be marked as brainliest for brainly. Q no 5 and 6 will be regarded as talented person

Answer 1

Ans for qns 5 is 1000 N
Since the car moves with constant velocity there is no acceleration thus applied force equals to frictional force.

Ans for qns 6i) is 25m
Distance travelled is equal to area under velocity-time graph. Thus distance= area of triangle is 0.5x2x25

Ans for qns 6ii) is 12500N
Acceleration = gradient of BD = -12.5 ms^-2
F=ma = 1000 x 12.5 = 12500N

Hope it helps.

Answer 2

hey buddy.....

thank you for question.....

here's your answer dude....

5)as per your question car is moving constantly at velocity of 30km/hr and applied force is 1000N

so as car is moving constantly it will remain at 1000N

6)i)answer is 25m

Distance travelled = are under time velocity-time graph thus distance =Area of traingle=0.5×2×25

6)ii) answer is 12500N

acceleration=-12.5m/s^-2(here both minus and minus cancel out each other)

f=ma=1000×12.5

=12500N

hope it helps mark me as brainliest.....