Question

the ones digit of a 2-digit number is three times the tens digit and the sum of digits is 8. Find the number.

Answer 1

Let the once digit number be x and the tens digit number be y. Therefore x=3y and x+y =8 applying x=3y,in x+y=8 therefore y+3y =8. 4y=8and y=2.y=2in x=3y we get x=2*3=6there for the number is 26

Answer 2

Answer:

26

Step-by-step explanation:

Let the digit at the ones place be x and the digit at the tens place be y

A/Q

x=3y,------(1)

and x+y=8(given)------(2)

putting the value of (1) in (2)

3y+y=8

4y=8

y=2

putting the value of y in (1)

x=3×2

x=6

two digit no =10y+x

=10×2+6

=20+6=26