the ones digit of a two-digit number is thrice the tens digit,if the digits are interchanged, the new number becomes 10 more than twice the old number, find the number
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Answered by
26
Answer:
hey here is your answer
pls mark it as brainliest
Step-by-step explanation:
so let the two digit number be 10x+y
wherein digit at ones place be y and that of tens be x
so according to first condition
y=3x (1)
according to second condition
10y+x=10+2(10x+y)
ie 10y+x=10+20x+2y
ie 19x-8y=-10 (2)
so substitute value of y from (1) in (2)
we get 19x-24x=-10
ie -5x=-10
ie x=2
so substitute value of x in (1)
we get y=6
our assumed two digit number was
10x+y=(10×2)+6
=20+6
=26
hence the required two digit number is 26
Answered by
6
Answer:
26 is the answer
Step-by-step explanation:
Mark as brainlist
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