Question

the ones digit of a two digit number is twice the tens digit. when the number formed by reversing the digits is added to the original number, the sum is 99. find out the original number

Answer 1

hey mate !! this is your answer

When the number formed by reversing the digits is added to original number,the sum is 99.Find the original number
**
let u=ones digit
let t=tens digit
u=2t

hope it helps

Answer 2

Answer:

Let, the tens digit number be x.

Thus, the ones digit =2x

Thus digit formed is (10×x) + 2x

= 10x + 2x

= 12x

After changes,

Digit at tens place = 2x

Digit at ones place = x

Thus, the formed is (10×2x)+x

= 20x + x

= 21x

A.T.Q., we've

12x + 21x = 99

= 33x = 99

= x = 99 × 1/33

= x = 3

Thus , the original number is (10 × x) + 2x = (10 × 3)+2 × 3

= 30+6

= 36

Thank you

Please mark me as brainliest