Math, asked by jabonetenicole, 3 months ago

The ones’ digit of a two-unit digit number is twice its tens digit. If the digits are interchanged, the new number will be 36 more than the original number. What is the original number?

Answers

Answered by RvChaudharY50
0

Answer :-

Let digits at ten's place = x

So,

digits at one's place = 2x .

A/q,

→ Interchanged number - original number = 36

→ [10*2x + x] - [10*x + 2x] = 36

→ 21x - 12x = 36

→ 9x = 36

→ x = 4 .

then,

→ Original number = 10x + 2x = 10*4 + 2*4 = 40 + 8 = 48 (Ans.)

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