The only value of for which the quadratic polynomial kr +x+k has equal zeroes is 1/2
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Answered by
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Answer:
The value of k is either \frac{1}{2} or -\frac{1}{2}.
Step-by-step explanation:
The given polynomial is
p(x)=kx^2+x+k
A polynomial f(x)=ax^2+bx+c has equal roots if
b^2-4ac=0
1^2-4(k)(k)=0
1-4k^2=0
1=4k^2
\frac{1}{4}=k^2
\pm\sqrt{\frac{1}{4}}=k
\pm\frac{1}{2}=k
Therefore the value of k is either \frac{1}{2} or -\frac{1}{2}.
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Answered by
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K/4+1/2+k=0
K+2+4K =0
5k=-2
K=-2/5
K+2+4K =0
5k=-2
K=-2/5
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