The open loop gain A = 2 x 10^{4}10 4
, where v_{o}v o
=−Av_{s}v s
.
The positive supply voltage for the op-amp is +V_S = 15+V S
=15V. The negative supply voltage for the op-amp is -V_S = -10−V S
=−10V.
what is the most negative value v_{s}v s
can take before the amplifier saturates? Express your answer in mV and omit units from your answer.
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Answer:
MERKO NHI PATA
Explanation:
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