Question

The opposite angles of a parallelogram are (3x+5)0 and( 61-x)0. Find the measure of four angles.

Answer 1

Answer:

sum of opposite angles of a parallelogram =180°

(3x+5)+(61-x)=180°

2x+66=180

2x=180-66

2x=114

x=114÷2

x=57

one angle =3x+5=3×57+5=176

second=61-x=61-57=4

third=180-176=4(co interior angles)

forth=180-4=176(,, ,, ,, )

Answer 2

Answer:

47°,47°,133°,133°

Step-by-step explanation:

The opposite angles of a parallelogram are equal

so (3x+5)° =( 61-x)°

3x+5=61-x

3x+x=61-5

4x=56

x=14

hence the measure of the given opposite angles

=3x+5=3*14+5=42+5=47°

Let the opposite angles are ∠A and ∠C

so  ∠A =∠C=47°

∠B is adjacent angle

so ∠A+∠B=180

47+∠B=180

∠B=180-47=133°

Also ∠D=∠B=133°

So four angles are

47°,47°,133°,133°