the opposite angles of a parallelogram are equal proof practicaly
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I have attached a image here, do check it that is the proof.
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We know that JK ll ML and the transversal JK intersect the two ll Lines
In ∆ JML and LKJ :
angle MJK=angle KLM {alternate interior angle}
angle KJL = angle MLJ {alternate interior angle}
JL =LJ{common side}
thus, the to triangle are congruent by the ASA congruencey of triangles.
since, ∆ JML=LKJ , angle M = angle K
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