Question

the opposite angular points of a square are 5 ,4and minus 1,6 find the coordinates of remaining 2 vertices

Answer 1

hola there
we know, 
properties of square : 
(1) all sides are equal 
(2) angle between two sides = 90° 

use this concept here, 
Let one unknown point of square is C(P, Q) given, A( 5, 4) , D(-1, 6) 

AC = DC 
AC² = DC² 
(P-5)² + (Q -4)² = (P+1)² + (Q -6)² 
-10P +25 -8Q + 16 = 2P +1 -12Q + 36 
-12P + 4Q + 4 = 0 
-3P + Q + 1 = 0 ________(1)

AC² + DC² = AD²
(P+1)² + (Q -6)² + (P-5)² + (Q -4)² = (6)² + (2)² 
2P² + 2Q² -8P -20Q + 78 = 40 
P² + Q² -4P - 10Q + 19 = 0-----------(2)
from (1) and (2) 

P² + (3P-1)² -4P -10(3P-1) + 19 = 0
10P² +1 - 6P -4P -30P +10 + 19 = 0
10P² - 40P + 30 = 0
P² -4P + 3 = 0
P = 1 and 3 
Q = 3P -1 = 2 and 8 
hence, 
two unknown points of square are 
( 1 , 2) and (3, 8)