Chemistry, asked by chimu1455, 9 months ago

The order of decreasing stability of the carbanions
(CH₃)₃C⁻(I);(CH₃)₂CH⁻; (II)CH₃CH⁻₂; (III)C₆H₅CH⁻₂ (IV) is
(a) I > II > III > IV (b) IV > III > II > I
(c) IV > I > II > III (d) I > II > IV > III

Answers

Answered by vishwacharanreddy201
1

correct option is 4. |>||>|V>|||

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