Question

The ordered pairs of positive integers are arranged in a sequence: (1, 1), (1, 2), (2, 1), (1, 3), (2, 2), (3, 3), (1, 4), ........ . Following the rule: if two ordered pairs have a different element-sum, the one with the smaller element-sum comes first and if they have the same element-sum, the one with the smaller first element comes first. In this arrangement, the 1978th ordered pair is (a, b), then find the value of (2a –

Answer 1

Answer:

ok

Step-by-step explanation:

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