Chemistry, asked by Prashant5033, 1 year ago

The organic compound liberated in the electrolysis of an aqueous solution of potassium succinate is

Answers

Answered by Benipal07

3

it forms CH2=CH2 + 2 CO2 + H2 + 2 KOH

Answered by Grewal007

0

it forms CH2=CH2 + 2 CO2 + H2 + 2 KOH Answer:

Explanation:

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