The origin of coordinate axes shifted to (-1,3) and axes is rotated through an angle 90° in the positive direction. If a,b is new coordinates for 2,3 find valenof 2a^2 and 3b^2
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Answer:
Origin is shifted to (2,−3)=>Co-ordinatede (x,y) will become (x−2,y+3)
So (i) (5,2) becomes (5−2,2+3)=(3,5)
(ii)(2,−7) becomes (2−2,−7+3)=(0,−4)
(iii)(3,−4) becomes (3−2,−4+3)=(1,−1)
(iv)(−10,3) becomes (10−2,3+3)=(8,6)
(v)(2,-3) becomes (2−2,−3+3)=(0,0)
Step-by-step explanation:
hope this helps u
Answered by
1
Answer:
Answer:
Origin is shifted to (2,−3)=>Co-ordinatede (x,y) will become (x−2,y+3)
So (i) (5,2) becomes (5−2,2+3)=(3,5)
(ii)(2,−7) becomes (2−2,−7+3)=(0,−4)
(iii)(3,−4) becomes (3−2,−4+3)=(1,−1)
(iv)(−10,3) becomes (10−2,3+3)=(8,6)
(v)(2,-3) becomes (2−2,−3+3)=(0,0)
Step-by-step explanation:
hope this helps u
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