the original equation is ¼x + y = 2, what is the transformed equation of these original equation?
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Answer:
Step-by-step explanation:
The given equation is x
3
−
4
1
x
2
+
3
1
x−
144
1
=0
Multiplying the roots of the given equation by m, the transformed equation is
x
3
−
4
1
mx
2
+
3
1
m
2
x−
144
1
m
3
=0
⇒x
3
−
2
2
1
mx
2
+
3
1
m
2
x−
2
4
.3
2
1
m
3
=0
Clearly the least value of m to remove the fractional coefficient is m=2
2
.3=12
Therefore putting this, we get
x
3
−
2
2
1
(2
2
.3)x
2
+
3
1
(2
2
.3)
2
x−
2
4
.3
2
1
(2
2
.3)
3
=0
⇒x
3
−3x
2
+48x−12=0
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