Question

The osmotic pressure of 2.22 % (w/v) CaCl2

solution at 27°C is​

Answer 1

Answer:4.926

Explanation:

Answer 2

Given:

w/v % of CaCl2 = 2.22 %

T = 27 °C = 300 K

To Find:

The osmotic pressure of CaCl2  solution.

Calculation:

- Let the volume of solution be 100 ml.

⇒ The mass of CaCl2 = 2.22 gm

- Molar mass of CaCl2, M.wt = 111 gm

- Molarity = (w×1000)/(M.wt×V)

⇒ M = (2.22×1000)/(111×100)

⇒ M = 0.2 M

- Osmotic pressure = C R T

⇒ Π = 0.2 × 0.082 × 300

⇒ Π = 4.92 atm

- SO, the osmotic pressure of 2.22 % (w/v) CaCl2  solution at 27°C is 4.92 atm.