Question

The osmotic pressure of a decimolar solution of urea at 27 degrees Celsius is

Answer 1

We will use the formula, cRT
​Decimolar solution is that, concentration of solution is 1/10 M or 0.1 M solution.
So,
V = 1 L
c = 0.1 mol
T = 27 C = 273 K + 27 = 300 K
​R = 0.0821 L atm K-1 mol-1
 = cRT / V
  = 0.1 mol × 0.0821 L atm K-1 mol-1 × 300K / 1 L
​ = 2.463 atm
​

Now, since 1 atm = 1.01325 bar
therefore, 2.463 atm = 2.463 × 1.01325 bar = 2.49 bar

I hope this will clarify your doubt.

Answer 2

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