Chemistry, asked by manishbabu, 1 year ago

The osmotic pressure of a decimolar solution of urea at 27 degrees Celsius is

Answers

Answered by Abhi6611
14
We will use the formula ,cRT
devi molar solution it that,concentration of solution is 1/10M or 0.1M solution.
so,
V= 1L
c=0.1mol
T.= 27c= 273K+27=300K
R=0.0821L atm. K-1 mol-1
=cRT/V
=0.1mol×0.0821L atm K-1 mol-1×300K/1L
=2.463atm.

Now,1 atm =1.01325bar
therefore,2.463 atm.=2.49bar
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