Question

The osmotic pressure of a solution containing 45g of sucrose dissolved per litre of solution at 20°C is 3.2atm. Calculate the value of constant R. (Molecular weight of sucrose=342)​

Answer 1

heres ur answer enjoy!

Plz refer the attachment

Answer 2

R = 0.084 .

Explanation:

We know,

Osmotic pressure, $\pi=i\times C\times R\times T .$

Here, R is constant which we have to find.

C is concentration of the solution.

i is vont hoff factor i.e 1 ( because sucrose does not dissociate in water and we considering water to be solvent).

T is temperature of the system.

Now, $C=\dfrac{no\ of\ moles}{Volume \ in\ liters}=\dfrac{no\ of\ moles}{1}$

no of moles = $\dfrac{Given\ mass}{molecular\ mass}=\dfrac{45}{342}=0.13\ moles$

Therefore, concentration C =$\dfrac{0.13}{1}=0.13\ M.$

Also, T = 20+273 = 293 K .

Putting all these values.

We get R = 0.084 .

Hence, this is the required solution.

Learn more :

Osmotic Pressure.

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