Question

The area of rectangle 2400m squre and its length is 6 times the breadth then find the perimeter

Answer 1

Question :The area of rectangle 2400 m^2 and its length is 6 times the breadth then , find the perimeter.

Solution :

$\underline{\bold{Given:}}$

• $Area\: of \:rectangle = 2400 \:m^2$

$\underline{\bold{To\:Find:}}$

• Perimeter of rectangle.

Let the breadth of rectangle be x m.

Then, its length = 6x m

$\boxed {\pink {Area \:of\: rectangle = length \times breadth}}$

Atq,

$\implies \: Area = length \times breadth \\ \implies2400 = 6x \times x \\ \implies2400 = 6 \: {x}^{2} \\ \implies \frac{2400}{6} = {x}^{2} \\ \implies400 = {x}^{2} \\ \implies \sqrt{400} = x \\ \implies \sqrt{20 \times 20} = x \\ \implies 20 = x \\\implies x = 20$

$Length= (6 \times 20) \: m = 120 \: m\\Breadth = 20 \: m$

$\boxed{\blue{Perimeter =2(length+breadth)}}$

$\implies Perimeter =2(length+breadth) \\ \implies Perimeter = 2(120 \: m + 20 \: m) \\ \implies Perimeter =2 \times 140 \: m \\ \implies Perimeter =280 \: m$

$\fbox {\green {Perimeter \:of\: rectangle= 280\:m}}$

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