Question

the outer and inner circumference of a circular road are 462 M and 440 metre respectively find the width of the road

Answer 1

3.5 is answer
462=2×22/7×R
so R= 73.5....
440=2×22/7×r
so r=70....put the value in formula
R-r = 73.5-70.3=3.5

Answer 2

The width of road is 3.5 m

Step-by-step explanation:

Circumference of circle =$2 \pi r$

Let the radius of outer circle be R and inner circle be r

Outer circumference = $2 \pi R$

We are given that outer circumference is 462 m

So,$2 \pi R = 462 \\2 \times \frac{22}{7} \times R = 462\\R = \frac{462 \times 7}{2 \times 22}\\R=73.5$

Inner circumference =$2 \pi r$

We are given that inner circumference is 440 m

So, $2 \pi r = 440 \\2 \times \frac{22}{7} \times r=440\\r= \frac{440 \times 7}{2 \times 22}\\r=70$

Width of road = Outer radius - Inner radius = 73.5 - 70 = 3.5 m

Hence The width of road is 3.5 m

#Learn more:

A circular road runs round a circular garden. if the circumference of the outer circle and the inner are 110 m and 88 m. find the width of the road

https://brainly.in/question/2948937