The outer and inner diameters of a hemispherical bowl are 17cm and 15cm find the cost of polishing it over at 25 paisa percm2
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Curved surface rea of hemisphere.
For outer CAS
= 2pi R^2
=2 pi 17*17
=289*2*pi
=578pi
For inner CSA
=2pi r^2
=2*pi*15*15
=225*2*pi
=450pi
Now area of ring....
=2 pi(R^2 - r^2)
=2 pi (17^2 - 15^2)
=2 pi (289 - 225)
=2 pi 64
=138pi..
Total area to be polise
=578pi+450pi+138pi
=1166 pi
= 1166*22/7
=3664.6 cm^2
Cost of polishing
= 3664.4*24
=87950.4paisa
=87950.4/100
=rupee 879.5
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