Math, asked by anuragkumarrtp, 1 year ago

The outer diameter of a iron pipe is 14cm and the thickness of the pipe is 1 cm .find the weight of 5m long tube if the density of the iron is 7gm/cm^3.

Answers

Answered by prernajoshi131994
1

volume of the cylinder= 22/7 (14^2- 13^2) 500

density= mass /volume

mass= vol of cylinder * 7 =297000gm or 297 kg


anuragkumarrtp: Wrong
anuragkumarrtp: 143kg
Answered by JackelineCasarez
2

Answer:

Weight of the iron pipe is 142870 g .

Step-by-step explanation:

Formula

Density = \frac{Mass}{Volume}

As given

The outer diameter of a iron pipe is 14cm and the thickness of the pipe is 1 cm .

The length of the tube is 5 m .

As

1m = 100 cm

Length of the tube = 500 cm

Radius = \frac{Diameter}{2}

Radius = \frac{14}{2}

                  = 7 cm

Let us assume that the outer radius is defied by R .

Let us assume that the inner radius is defied by r .

Thus

R = 7 cm

r = Outer radius - Thickness of pipe

r = 7 - 1

  = 6 cm

Volume\ of\ the\ pipe = \pi (R^{2}-r^{2})\times h

\pi = 3.14

Volume\ of\ the\ pipe =3.14\times (7^{2}-6^{2})\times 500

Volume\ of\ the\ pipe =3.14\times (49-36)\times 500

Volume\ of\ the\ pipe =3.14\times 13\times 500              

                                            = 20410 cm³

As given

if the density of the iron is 7gm/cm³.

Put all the values in the formula

7 = \frac{Mass}{20410  

Mass = 7 × 20410

         = 142870 g

Therefore the weight of the iron pipe is 142870g .

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