The outer diameter of a iron pipe is 14cm and the thickness of the pipe is 1 cm .find the weight of 5m long tube if the density of the iron is 7gm/cm^3.
Answers
volume of the cylinder= 22/7 (14^2- 13^2) 500
density= mass /volume
mass= vol of cylinder * 7 =297000gm or 297 kg
Answer:
Weight of the iron pipe is 142870 g .
Step-by-step explanation:
Formula
As given
The outer diameter of a iron pipe is 14cm and the thickness of the pipe is 1 cm .
The length of the tube is 5 m .
As
1m = 100 cm
Length of the tube = 500 cm
= 7 cm
Let us assume that the outer radius is defied by R .
Let us assume that the inner radius is defied by r .
Thus
R = 7 cm
r = Outer radius - Thickness of pipe
r = 7 - 1
= 6 cm
= 20410 cm³
As given
if the density of the iron is 7gm/cm³.
Put all the values in the formula
Mass = 7 × 20410
= 142870 g
Therefore the weight of the iron pipe is 142870g .