Question

the outer radius of a spherical container is 7 cm and the thickness of the container is 3cm .find the vo​
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Answer 1

Given :-

The outer radius of a spherical container = 7 cm

The thickness of the spherical container = 3 cm

To Find :-

The volume of the spherical container.

Analysis :-

Since there are outer and inner radius as well as the thickness; then make the equation accordingly by the formula of volume and subtract the given radiuses.

Solution :-

We know that,

• r = Radius
• v = Volume

Given that,

Radius (r) = 7 cm

Thickness = 3 cm

Inner radius = Radius - Thickness

= 7 - 3 = 4 cm

By the formula,

$\underline{\boxed{\sf Volume \ of \ a \ sphere=\dfrac{4}{3} \pi r^3}}$

According to the question,

$\sf \dfrac{4}{3} \pi [(Outer \ radius)^3 - (Inner \ radius)^3]$

$\sf =\dfrac{4}{3} \times \dfrac{22}{7} \times [(7)^3-(4)^3]$

$\sf =\dfrac{4}{3} \times \dfrac{22}{7} \times (343 - 64)$

$\sf =\dfrac{4}{3} \times \dfrac{22}{7} \times 279$

$\sf =4 \times \dfrac{22}{7} \times 93$

$\sf =4 \times 22 \times 13.28$

$\sf =1168.64 \ cm^3$

Therefore, the volume of the spherical container is 1168.64 cm³.

Answer 2

Answer:

Given :-

The outer radius of a spherical container = 7 cm

The thickness of the spherical container = 3 cm

To Find :-

The volume of the spherical container.

Analysis :-

Since there are outer and inner radius as well as the thickness; then make the equation accordingly by the formula of volume and subtract the given radiuses.

Solution :-

We know that,

r = Radius

v = Volume

Given that,

Radius (r) = 7 cm

Thickness = 3 cm

Inner radius = Radius - Thickness

= 7 - 3 = 4 cm

By the formula,

Volume=4/3πr^3

According to the question,

4/3π[(ounter radius)^3-(Inner radius)^3]

=4/3 X 22/7 X [(7)^3-(4)^3]

=4/3 X 22/7 X (343-64)

=4/3 X 22/7 X 279

=4/3 X 22/7 X 93

=4 X 22 X 13.28

=1168.64Cm^3

Therefore, the volumeofthespherical container is 1168.64 cm³.