the outer radius of metallic sphere is 6 cm and its inner radius is 3 cm find the volume of the metal used in it
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0
It is 792cm^{2}
R=6cm
r=3cm
Volume=4/3\pi(R^{3}-r^{3})
=4/3*22/7*(216-27)
=792cm^2
R=6cm
r=3cm
Volume=4/3\pi(R^{3}-r^{3})
=4/3*22/7*(216-27)
=792cm^2
Answered by
3
Outer Radius = 6 cm
Inner Radius = 3 cm
Volume of metal used = Outer Volume - Inner Volume
Volume of metal used = 4/3 * pi*6^3 - 4/3 * pi*3^3
= 4pi/3 (216 - 27)
= 4pi * 189 / 3
= 4*22*189/ 21
= 88*9
= 792 cm^3
Hope it help you
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Inner Radius = 3 cm
Volume of metal used = Outer Volume - Inner Volume
Volume of metal used = 4/3 * pi*6^3 - 4/3 * pi*3^3
= 4pi/3 (216 - 27)
= 4pi * 189 / 3
= 4*22*189/ 21
= 88*9
= 792 cm^3
Hope it help you
Please mark as brainliest if you liked the solution
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