The outer surface of an electric kettle is always kept polished and shiny to
A) gain energy by conduction
B) reflect any radiation incident on its outer surface
C) reduce energy loss by thermal conduction
D) reduce energy loss through radiation
Answers
Answered by
2
hii mate ....
ur answer is (c)
hope this helped u..
ur answer is (c)
hope this helped u..
Anonymous:
especially the ones who r unknown.
Answered by
47
Here is your answer
Option (D) reduce energy loss through radiation.
This is because Shiny and polished surfaces are poor emitters of radiations. Hence they reduce heat loss where as rough and dull surfaces are good emitters of radiations
i.e If there is tea in a kettle which is shinny towards outside remains hot for longer time due to comparatively less heat loss.
Hope it helps you
Option (D) reduce energy loss through radiation.
This is because Shiny and polished surfaces are poor emitters of radiations. Hence they reduce heat loss where as rough and dull surfaces are good emitters of radiations
i.e If there is tea in a kettle which is shinny towards outside remains hot for longer time due to comparatively less heat loss.
Hope it helps you
Similar questions