Physics, asked by MathLoverAreen, 1 year ago

The outer surface of an electric kettle is always kept polished and shiny to
A) gain energy by conduction
B) reflect any radiation incident on its outer surface
C) reduce energy loss by thermal conduction
D) reduce energy loss through radiation

Answers

Answered by Anonymous
2
hii mate ....

ur answer is (c)

hope this helped u..

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Answered by rajeev378
47
Here is your answer

Option (D) reduce energy loss through radiation.

This is because Shiny and polished surfaces are poor emitters of radiations. Hence they reduce heat loss where as rough and dull surfaces are good emitters of radiations
i.e If there is tea in a kettle which is shinny towards outside remains hot for longer time due to comparatively less heat loss.

Hope it helps you

rajeev378: Thanks for the brainliest
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