Question

The oxidation and coordination number of cr in [cr(c2o4)3]3- is

Answer 1

Here c2o4 oxalate ion has a charge of -2 and the total charge of complex ion is -3 so going mathematically,

Let charge of cr be x,

Then,

x + 3(-2) = -3

x -6 = -3

x = 6 - 3

x= 3

Therefore charge of cr in [cr(c2o4)3]3- is +3.

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Answer 2

Answer:

answer will be 6

Explanation:

So, as c2o4 is bidentate hence the coordination number of Cr will be six.

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