The oxidation number of "C" in CH⁴ molecule is
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Charge of the molecule is 0. Charge of the molecule is 0. Charge of the molecule is 0. Since, the oxidation numbers of C in CH4 , CH3Cl , CH2Cl2 , CHCl3 and CCl4 are −4,−2,0,+2,+4 respectively.
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Answer:
x + 4(+1)=0
x= -4
Explanation:
carbon has a oxidation state of -4
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