Question

the oxidation number of Fe in the compound k3[Fe(CN)6].

Answer 1

hey buddy➡➡➡➡


➖➖oxidation No of Fe(iron) in potassium ferric cyanate is +3


solution::: K3= +1×3= +3

CN= -1, since there are 6 atoms = -6

then,,

oxidation no==>>. 3+ x + 6×(-1)= 0

3+x-6= 0

x-3=0

x= 3...

⏹⏹hope it helps

Answer 2

we have,

The compound K3[Fe(CN)6] can be written as
$3 {K}^{ + } {Fe(CN6)}^{3 - }$
Now,

whole charge on CN is -1. (Learn it).

Let ,in the compound Fe(CN)6^3- ,the oxidation number of Fe is x.

now, according to sum rule,

x + (-1) × 6 = -3.

=> x - 6 = -3

=>x = 3

Thus the oxidation number of Fe in compound is 3.

Regards

KSHITIJ